What is the product of #(x/4-1/3)*(x/4+1/3)#?

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Answer 1 · 2016-11-24T17:09:20

#(9x^2 - 16)/144#

First, get all of the fractions over a common denominator by multiplying by the appropriate form of #1#:

#((3/3)(x/4) - (4/4)(1/3)) * ((3/3)(x/4) + (4/4)(1/3)) =>#

#((3x)/12 - 4/12) * ((3x)/12 + 4/12) =>#

#(3x - 4)/12 * (3x + 4)/12#

Now we can cross multiply the numerators and multiply the denominators:

#(9x^2 - 12x + 12x - 16)144 =>#

#(9x^2 - 16)/144#