How do you find the common ratio for $10,5,5/2,5/4,5/8,...$ ?

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Answer 1 · 2016-11-25T09:05:43

$10xx1/2=2; 5xx1/2=5/2; 5/2xx1/2=5/4; 5/4xx1/2=5/8; 5/8xx1/2=5/16............$

The $n^(th)$ term is $10/2^(n)$ , $n=0,1,2,3.....$

To find the ratio divide successive terms: $10/5=2;5xx2/5=2;5/2xx4/5=2$ .

How do you find the common ratio for 10,5,5/2,5/4,5/8,...10,5,5/2,5/4,5/8,...?