How do you divide $\frac{- 6 - i}{i}$ $(-6-i)/i$ ?

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Answer 1 · 2016-11-27T01:21:22

$- 1 + 6 i$ $-1+6i$

$\frac{- 6 - i}{i} = \frac{(- 6 - i) \cdot i}{i \cdot i}$ $(-6-i)/i = ((-6-i)*i)/(i*i)$

$= \frac{- 6 i - (- 1)}{- 1}$ $= (-6i-(-1))/-1$

$= \frac{- 6 i + 1}{- 1}$ $=(-6i+1)/-1$

$= - 1 + 6 i$ $=-1+6i$

How do you divide (-6-i)/i−6−ii(-6-i)/i?