If a rocket with a mass of 3500 tons vertically accelerates at a rate of # 2/5 m/s^2#, how much power will the rocket have to exert to maintain its acceleration at 4 seconds?

1 Answer
Nov 27, 2016

2240000 Watts

Explanation:

Firstly,
We know, Power = Force x Velocity

For the force, we know that F = m x a , where m is the mass and a is the acceleration of the body.

In this case,

F = 3500 x 1000 x #2/5#, where 1000 is for converting tons to kg.

So, F = 1,400,000 Newtons.

Now we need to find the velocity at 4 s.

We know that a = #2/5# #ms^2#, t = 4s, initial velocity ( u) = 0 #ms^2#,
So,

a = #(v - u) / t #
Therefore, v = 1.6 #ms^2#

So,
P = 1,400,000 x 1.6 = 2240000 Watts.