How do you solve #-e^(6-9p)+5=-48.4#?

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Answer 1 · 2016-11-27T23:34:10

#p=1/9ln53.4-2/3#

#p approx -.2247#

#-e^(6-9p)+5=-48.4#

Subtract #5# from each side:
#-e^(6-9p)=-53.4#

Divide each side by #-1#:
#e^(6-9p)=53.4#

Rewrite as a natural log:
#ln53.4=6-9p#

Solve for p -- subtract 6 from each side:
#ln53.4-6=9p#

Divide each side by 9:
#frac{ln53.4-6}{9}=p#

Simplify:
#p=1/9ln53.4-2/3#