How do you evaluate #s^2tdiv10# for s=-2 and t=-10?

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Answer 1 · 2016-11-28T01:47:45

#-4#

First, rewrite this problem as:

#(s^2t)/10#

Now you can substitute the given values for #s# and #t# to evaluate the expression:

#((-2^2)*(-10))/10#

#((-2* -2)*(-10))/10#

#(4*(-10))/10#

#-40/10#

#-4#