Question

How do you solve `10( x - 2) = - 20`?

Answer 1

`x=0`

Explanation:

Solve `10(x-2)=-20`.

Expand the left-hand side using the distributive property, `a(b+c)=ab+ac`.

`10x-20=-20`

Add `20` to both sides.

`10x=-20+20`

`10x=0`

Divide both sides by `10`.

`x=0/10`

`x=0`

Answer 2

`x=0`

Explanation:

First, multiply `10(x-2)`. To multiply one number and numbers in parentheses, multiply the one number against every number or term in the parentheses (distributive property ), like this:
`3(x^2+10x+2)`
=`3x^2+30x+6`

So, apply it to the problem.
`10(x-2)`
`=10*x+10*(-2)`
=`10x-20`

Now, just simplify. You're trying to get x alone. When you do something to one side of the equation, you must do it to the other. So, add 20 to each side to cancel out the -20 on the x's side.
`10x-20=-20`
`10x-20+20=-20+20`
`10x=0`

Now, divide each side by 10 to get the x alone.
`(10x)/10=0/10`

`x=0`