How do you solve #3x + 6= 5#?

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Answer 1 · 2016-11-28T21:56:43

#x = -1/3#

Step 1) Subtract 6 from each side of the equation to isolate the #x# term and keep the equation balanced:

#3x + 6 - 6 = 5 - 6#

#3x + 0 = -1#

Step 2) Divide each side of the equation by #3# to solve for #x# and keep the equation balanced:

#(3x)/3 = (-1)/3#

#(cancel(3)x)/cancel(3) = -1/3#

#x = -1/3#