Question

What is the molarity of the NaOH if 41.67 ml of this solution is needed to neutralize 0.2625 grams of pure 3H_2C_2O_4 + 2H_2O#?

Answer 1

`sf(0.3975color(white)(x)"mol/l")`

Explanation:

`sf(H_2C_2O_4+2NaOHrarrNa_2C_2O_4+2H_2O)`

`:.`2 mol `sf(NaOH-=)` 1 mol `sf(H_2C_2O_4)`

`sf(n_(H_2C_2O_4)=m/M_r=0.2625/90.035=0.0029155)`

`:.` `sf(n_(NaOH)=0.0029155xx2=0.005831)`

`sf(c=n/v=0.005831/0.01467=0.3975color(white)(x)"mol/l")`