Question

What is the force, in terms of Coulomb's constant, between two electrical charges of `44 C` and `39 C` that are `12 m` apart?

Answer 1

The force '`F'=11.91k C^2//m^2`.

Explanation:

The coulomb's law gives `F=(k q_1q_2)/r^2`, where 'k' is the proportionality constant. It is also called as coulomb's constant as it as derived from coulomb's law.
Proportionality constant 'k' is equal to '`(1)/(4piepsilon_0)`'
so substituting the given values in above equation of coulomb's law we get,
.`F=(k(44C)(39C))/(12m)^2`
`:.` The force in terms of coulomb's constant 'k' is `11.9 k (C^2//m^2)~~12k(C^2//m^2)`