How do you solve #8\leq | 3x - 2|#?

1 Answer
Cronus G.
Nov 29, 2016

You have to do two solutions. Just to visualize it better, lets make it:
#|3x-2| >= 8#
Okay lets begin:

Explanation:

Two solutions!

1) #3x-2 >=8#
And solve for X like you would usually
#3x >=10#
#x >=10/3#
2) #-3x+2 >=8#
You make it negative, as shown up.
And solve for X
#-3x >=6#
#x <=6/-3#
#x <=-2#

So your final answers are:
#x >=10/3# & #x <=-2#

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