How do you solve 8\leq | 3x - 2|?

1 Answer
Nov 29, 2016

You have to do two solutions. Just to visualize it better, lets make it:
|3x-2| >= 8
Okay lets begin:

Explanation:

Two solutions!

1) 3x-2 >=8
And solve for X like you would usually
3x >=10
x >=10/3
2) -3x+2 >=8
You make it negative, as shown up.
And solve for X
-3x >=6
x <=6/-3
x <=-2

So your final answers are:
x >=10/3 & x <=-2