Question

How do you evaluate the limit `(x^3+27)/(x+3)` as x approaches `3`?

Answer 1

By substitution.

Explanation:

Because the limit of the denominator is not `0`, we can use substitution to evaluate the limit.

`lim_(xrarr3) (x^3+27)/(x+3) = ((3^3)+27)/((3)+3) = 54/9 = 6`