Question

How would you calculate the specific beat of silver, given that 280 g of the metal absorbed 136 calories when changed from 22.13°C to 30.79°C?

Answer 1

`c_"Ag"=0.056"cal"/("g"*^@"C")`

Explanation:

The equation you'll need is the following:

where `Q` is in calories, `c` is in `"cal"/("g"*^@"C")`, `m` is mass in grams, and `DeltaT` is the change in Celcius temperature. `DeltaT=T_"final"-T_"initial"`

`Q="136 cal"`
`m="280 g"`
`T_"initial"="22.13"^@"C"`
`T_"final"="30.79"^@"C"`
`DeltaT="30.79"^@"C"-"22.13"^@"C"`"="8.66"^@"C"#

Rearrange the equation to isolate `c`.

`c_"Ag"=Q/(mDeltaT)`

`c_"Ag"=(136"cal")/(280"g"*8.66^@"C")`

`c_"Ag"=0.056"cal"/("g"*^@"C")`