Question #7c8a4

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Question #7c8a4

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Answer 1 · 2016-12-01T05:54:20

$23 {ft}^{3}$ $23"ft"^3$

Explanation:

If Valerie has a calculator, she can just calculate that $\sqrt{500} \approx 22.36$ $sqrt(500) ~~ 22.36$ , and order the least whole number greater than that, meaning she should order $23 {ft}^{3}$ $23"ft"^3$ of cement.

If Valerie does not have a calculator, she can work out some squares of whole numbers to find out that

$22^{2} = 484 < 500 < 529 = 23^{2}$ $22^2 = 484 < 500 < 529 = 23^2$

As $22^{2} < 500 < 23^{2}$ $22^2 < 500 < 23^2$ , that means $22 < \sqrt{500} < 23$ $22 < sqrt(500) < 23$ . Thus, without calculating the actual value of $\sqrt{500}$ $sqrt(500)$ , she can still tell that $23$ $23$ is the least whole number which is greater than $\sqrt{500}$ $sqrt(500)$ , and then order $23 {ft}^{3}$ $23"ft"^3$ of cement.

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Question #7c8a4

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