Question

How do you convert 11.0 g `CH_3OH` to 0.490 M?

Answer 1

You want to make a methanolic solution in water whose concentration with respect to methanol is `0.490*mol*L^-1`?

Explanation:

And thus `"Moles of methanol"/"Volume of solution"` `=` `0.490*mol*L^-1`

`"Methanol"` has a formula mass of `32.04*g*mol^-1`.

And thus `((11.0*g)/(32.04*g*mol^-1))/"Volume of solution"=0.490*mol*L^-1`.

Upon rearrangement, `"Volume of solution"=((11.0*g)/(32.04*g*mol^-1))/(0.490*mol*L^-1)`, which is under `1*L`.

Is this answer dimensionally consistent? Does it give an answer in `L`, which is required?