How do you integrate #int 1/(x(lnx)^3)# by parts?
2 Answers
Dec 1, 2016
See answer below:
Dec 1, 2016
If I had a choice, I would not use parts, I would use the substitution
Explanation:
If I was told I needed to use parts, I would take
# = -1/(2(lnx)^2) +C#
(I know it isn't " really" integration by parts.)