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Answer 1 · 2016-12-02T05:33:29

#x=81/16#

#2/3x = 27/8#

The term containing #x# is isolated. Its coefficient is #2/3#. Multiply by #3/2#, the reciprocal of #2/3#, to isolate #x#.

#2/3x xx 3/2 = 27/8 xx 3/2#

Use the commutative and associative properties of multiplication to group the reciprocal with the coefficient.

#(2/3xx3/2)x = 27/8 xx 3/2#

When multiplying fractions, we follow #a/bxxc/d = (ac)/(bd)#

#(2xx3)/(3xx2)x = (27xx3)/(8xx2)#

#=>6/6x = 81/16#

#=>1x = 81/16#

#:.x=81/16#