How do you solve the system of equations #4x + 4y = 44# and #5x - 3y = - 57#?

1 Answer
Dec 2, 2016

#x = -3# and #y = 14#

Step 3) Substitute #14# for #y# in the solution to the first equation in Step 1) and calculate #x#:

#x = 11 - 14#

Explanation:

Sep 1) Solve the first equation for #x#:

#4x + 4y - 4y= 44 - 4y#

#4x = 44 - 4y#

#(4x)/4 = 44/4 - (4y)/4#

#x = 11 - y#

Step 2) Substitute #11 - y# for #x# in the second equation and solve for #y#:

#5(11 - y) - 3y = -57#

#55 - 5y - 37 = -57#

#55 - 8y = -57#

#55 - 8y - 55 = -57 - 55#

#-8y = -112#

#(-8y)/(-8) = (-112)/(-8)#

#y = 14#

Step 3) Substitute #14# for #y# in the solution to the first equation in Step 1) and calculate #x#:

#x = 11 - 14#

#x = -3#