How do you solve #-4x + 3= 19#?

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Answer 1 · 2016-12-02T20:48:53

#x = -4#

Step 1) Isolate the #x# term on one side of the equation and the constants on the other side of the equation while keeping the equation balanced:

#-4x + 3 - 3 = 19 - 3#

#-4x + 0 = 16#

#-4x = 16#

Step 2) Solve for #x# while keeping the equation balanced:

#(-4x)/-4 = 16/-4#

#(cancel(-4)x)/cancel(-4) = -4#

#x = -4#