How do you solve #\frac { y } { 3} + 4= \frac { 2} { 5} y - 6#?

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Answer 1 · 2016-12-03T04:00:22

#y = 150#

Step 1) Multiple each term by a common denominator (I will use 15) to eliminate the fractions and keep the equation balanced:

#15(y/3 + 4) = 15(2/5y - 6)

#(15y)/3 + 4*15 = (15*2)/5y - 15*6#

#5y + 60 = 6y - 90#

Step 2) Isolate the #x# terms on one side of the equation and the constants on the other side of the equation while keeping the equation balanced:

#5y + 60 - 5y + 90 = 6y - 90 - 5y + 90#

#150 = y#

#y = 150#