How do you solve #25-3u=2u#?

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Answer 1 · 2016-12-03T12:14:07

#u = 5#

First, isolate the #u# term on one side of the equation and the constant on the other side of the equation while keeping the equation balanced:

#25 - 3u + 3u = 2u + 3u#

#25 - 0 = (2 + 3)u#

#25 = 5u#

Now solve for #u# while keeping the equation balanced:

#25/5 = (5u)/5#

#5 = (5/5)u#

#5 = 1u#

#u = 5#