Question

If the actual yield of `PBr_3` s found to be 22.3 g, how do you find the percent yield in this reaction?

The reaction between phosphorus and liquid bromine is outlined as: `2P(s) + 3Br_2(l) -> 2PBr_3(l)`

Answer 1

You cannot assess the percentage yield in this reaction.

Explanation:

`P+3/2Br_2 rarr PBr_3`

You have reported a mass of `"phosphorus bromide"` that is recovered. There are no data with respect to the amount of bromine or phosphorus used to synthesize the tribromide.

`"Moles of"` `PBr_3=(22.3*g)/(270.69*g*mol^-1)=??mol`.

So, you know the minimum quantities of bromine and phosphorus used in the synthesis reaction. You do not know the actual quantities utilized.