Question

How do you find the limit of `x^(x/4)` as x approaches infinity?

Answer 1

`x^(x/4) = e^(x/4lnx)` `rarr 00` as `xrarroo`

Explanation:

`x^(x/4) = e^(x/4lnx)`

As `xrarroo` we also have `x/4lnx rarr oo`, so `e^(x/4lnx) rarr oo`