How do you factor #3x^{2}-18x-81=0#?

1 Answer
Meave60
Dec 4, 2016

#3(x+3)(x-9)=0#

Explanation:

Factor #3x^2-18x-81=0#.

Each term is divisible by #3#. Factor out the #3# from each term.

#3(x^2-6x-27)=0#

Determine two numbers that when added equal #-6# and when multiplied equal #-27#. The numbers #-9# and #3# meet the criteria.

Rewrite the equation as #3(x+3)(x-9)=0#.

Related questions
Impact of this question
697 views around the world
You can reuse this answer
Creative Commons License