Question

How do you multiply `3x ( x ^ { - 2} y ^ { 3} )`?

Answer 1

`3y^3x`
to set negative power of x into positive ; put it to the denominator

Explanation:

`3x (x^-2y^3) = 3x(y^3)/x^2 = 3y^3/x`

Answer 2

`3x(x^-2y^3)=(3y^3)/x`

Explanation:

`3x(x^-2y^3)=(3x)xxx^-2xxy^3`

`=(3cancelx)xx1/cancel(x)xx1/(x)xxy^3`

`=(3y^3)/(x)` as required.........

Answer 3

`(3y^3)/x`

Explanation:

Using the `color(blue)"law of exponents"`

`color(orange)"Reminder " color(red)(bar(ul(|color(white)(2/2)color(black)(a^mxxa^n=a^(m+n)" and " a^-mhArr1/a^m)color(white)(2/2)|)))`

`rArr3x(x^-2y^3)=3x^1xxx^-2xxy^3`

`=3x^(1+(-2))y^3=3x^-1y^3`

`=3xx1/x xxy^3=(3y^3)/xlarr" positive exponents"`