The vertex form of the equation of a parabola is #y + 10 = 3(x-1)^2# what is the standard form of the equation?

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Answer 1 · 2016-12-05T18:34:08

y= #3x^2 -6x-7#

Simplify the given equation as

#y+10= 3 (x^2 -2x +1)#
Therefore y= #3x^2 -6x +3-10#

Or, y= #3x^2 -6x-7#, which is the required standard form.

Answer 2 · 2016-12-05T18:34:17

#y = 3x^2 - 6x - 7#

Please see the explanation for the steps.

Expand the square using the pattern #(a -b)^2 = a^2 - 2ab + b^2#

#y + 10 = 3(x^2 -2x + 1)#

Distribute 3 through the ()s:

#y + 10 = 3x^2 - 6x + 3#

Subtract 10 from both sides:

#y = 3x^2 - 6x - 7#

This is standard form.