How do you solve #1>=4x+9#?

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Answer 1 · 2016-12-07T14:34:01

#x <= -2#

First, isolate the #x# term on one side of the inequality while keeping the inequality balanced:

#1 - 9 >= 4x + 9 - 9#

#-8 >= 4x + 0#

#-8 >= 4x#

Next, solve for #x# while keeping the inequality balanced:

#(-8)/4 >= (4x)/4#

#-2 >= (cancel(4)x)/cancel(4)#

#-2 >= x#

Finally, to put the solution in terms of #x# we need to reverse or "flip" the inequality:

#x <= -2#