What is #\int 2x + 4#?

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Answer 1 · 2016-12-07T21:36:15

#int(2x+4)dx=x^2+4x#

Consider the power rule for integration:

#intx^ndx=(x^n+1)/(n+1)#

For the first part of your integrand:

#int2xdx=2intx^1dx=2(x^(1+1))/(1+1)=cancel2(x^2)/cancel2=x^2+c#

The second part is much more obvious:

#int4dx=4x+c# (Since the derivative of #4x+c# is #4#)

#:.int(2x+4)dx=x^2+4x+c#