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Answer 1 · 2016-12-09T10:54:29

You need 6 liters of pure antifreeze and 3 liters of 10%

Let #v=#volume of pure anti freeze

Then #9-v=#volume of #10%# anti freeze mixture

You write an equation , with respect to the quantity of anti freeze

#v*100%+(9-v)*10%=9*70%#

So,

#v+0.1(9-v)=9*0.7=6.3#

#v+0.9-0.1v=6.3#

#0.9v=5.4#

#v=5.4/0.9=6#

Volume of pure anti feeze #=6# liters

Volume of 10 % anti freeze #=3#liters