#lim_(x->oo)(x-1)/(2x+cos(x))=# ? Calculus Limits Determining Limits Algebraically 1 Answer Cesareo R. Dec 9, 2016 #1/2# Explanation: #(x-1)/(2x+cos(x))=x/x(1-1/x)/(2+cos(x)/x) = (1-1/x)/(2+cos(x)/x)# #lim_(x->oo)(x-1)/(2x+cos(x))=(lim_(x->oo)(1-1/x))/(lim_(x->oo)(2+cos(x)/x)) = 1/2# Note that #abs(cos(x)) le 1# Answer link Related questions How do you find the limit #lim_(x->5)(x^2-6x+5)/(x^2-25)# ? How do you find the limit #lim_(x->3^+)|3-x|/(x^2-2x-3)# ? How do you find the limit #lim_(x->4)(x^3-64)/(x^2-8x+16)# ? How do you find the limit #lim_(x->2)(x^2+x-6)/(x-2)# ? How do you find the limit #lim_(x->-4)(x^2+5x+4)/(x^2+3x-4)# ? How do you find the limit #lim_(t->-3)(t^2-9)/(2t^2+7t+3)# ? How do you find the limit #lim_(h->0)((4+h)^2-16)/h# ? How do you find the limit #lim_(h->0)((2+h)^3-8)/h# ? How do you find the limit #lim_(x->9)(9-x)/(3-sqrt(x))# ? How do you find the limit #lim_(h->0)(sqrt(1+h)-1)/h# ? See all questions in Determining Limits Algebraically Impact of this question 920 views around the world You can reuse this answer Creative Commons License