How do you find #lim (sqrtx-1)/(x-1)# as #x->1^+# using l'Hospital's Rule or otherwise?
1 Answer
Dec 9, 2016
I wouldn't use l'Hospital for this.
Explanation:
I would factor:
# = lim_(xrarr1) 1/(sqrtx+1) = 1/(1+1) = 1/2#
(Of course, I wouldn't write all that if I wasn't trying to explain.
OR
"Rationalize the numerator by multiplying by