Question

How do you solve `\sqrt { c + 9} - \sqrt { c } > \sqrt { 3}`?

Answer 1

`0 le c < 3`

Explanation:

The feasible solutions must accomplish `c+9 ge 0 nn c ge 0` so
`c ge 0`

Now, `sqrt(c+9) > sqrt(c)+sqrt(3)` and squaring both sides

`c+9 >c+3 + 2sqrt(3c)` or

`3 > sqrt(3c)` then `0 le c < 3`