Question

The perimeter of a rectangle is 56 feet. The width of the rectangle is 8 feet less than the length. How do you find the dimensions of the rectangle?

Answer 1

Length`=L`, width`=W`

Explanation:

Then perimeter`=2L+2W=56`

We can replace `L=W+8`

`2(W+8)+2W=56->`
`2W+16+2W=56->` subtract 16
`2W+2W+cancel16-cancel16=56-16->`
`4W=40->W=40//4=10->L=10+8=18`

The dimensions are `18ftxx10ft`