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What is the angle between #<-9,4,0> # and #<-8,2,-7 >#?

1 Answer

Dec 11, 2016

#theta= cos^-1 0.7509= 41.33^o#

Explanation:

If the angle between the two vectors is #theta#, then #cos (theta)=( (-9)(-8) +(4)(2) +0(-7))/(sqrt((-9)^2 +4^2 +0) sqrt((-8)^2 + 2^2 +(-7)^2)#

=#80/(sqrt97 sqrt117#=0.7509

#theta= cos^-1 0.7509= 41.33^o#

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