How do you multiply #2( 4x - 3) ( 4x + 3)#?

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Answer 1 · 2016-12-11T20:15:17

#32x^2 - 18#

First, cross multiply the terms in parenthesis:

#2((4x*4x) + (4x*3) - (3*4x) - (3*3))#

#2(16x^2 + 12x - 12x - 9)#

#2(16x^2 + 0 - 9)#

#2(16x^2 - 9)#

Now, we can distribute the #2# across each term in the parenthesis:

#2*16x^2 - 2*9#

#32x^2 - 18#