How do you solve #x- 5= 3x + 2#?
1 Answer
Dec 12, 2016
Explanation:
To solve questions like these, we take all the variable terms, which are those terms with an
If we Add, Subtract, Multiply or Divide the same quantity from each side, the equation remains unaffected.
So, to bring all variable terms to one side, subtract
#x - x - 5 = 3x - x - 2#
#=> -5 = 2x + 2#
Next, take all the constant terms (those terms having a fixed value) to the other side by subtracting 2 from each side to get
#-5 - 2 = 2x + 2 - 2#
#=> -7 = 2x#
Now, divide both sides by 2 to leave only
#-7/2 = x# #color(white)("XXX") or # #color(white)("XXX")# #x = -7/2 = -3 1/2#