How do you solve #2( x + 3) - 4x = x - 9#?

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Answer 1 · 2016-12-12T12:52:46

#x = 5#

Step 1) Expand the term in parenthesis:

#2x + 6 - 4x = x - 9#

Step 2) Combine like terms on the left side of the equation:

#2x - 4x + 6 = x - 9#

#(2 - 4)x + 6 = x - 9#

#-2x + 6 = x - 9#

Step 3) Solve for #x# while keeping the equation balanced:

#-2x + 2x + 6 + 9 = x + 2x - 9 + 9#

#0 + 6 + 9 = x + 2x - 0#

#6 + 9 = x + 2x#

#15 = (1 + 2)x#

#15 = 3x#

#15/3 = (3x)/3#

#5 = (cancel(3)x)/cancel(3)#

#5 = x#