How do you solve #8+ 8x = x - 6#?

1 Answer
Dec 12, 2016

#x = -2#

Explanation:

The first step is to isolate the #x# terms on one side of the equation and the constants on the other side of the equation while keeping the equation balanced:

#8 - 8 + 8x - x = x - x - 6 - 8#

#0 + 8x - x = 0 - 6 - 8#

#8x - x = - 6 - 8#

Now you can combine like terms:

#(8 - 1)x = -14#

#7x = -14#

Finally, you can solve for #x# while keeping the equation balanced:

#(7x)/7 = (-14)/7#

#(cancel(7)x)/cancel(7) = -2#

#x = -2#