How many #CO_2# molecules are in #1.70 * 10^-2# mole of #CO_2#?

1 Answer
anor277
Dec 12, 2016

There are #1.70xx10^-2*molxxN_A# #CO_2# molecules, where.......

Explanation:

.......where #N_A="Avogadro's Number"# #=# #6.022xx10^23*mol^-1#.

And so, #1.70xx10^-2*molxxN_A=1.70xx10^-2*cancel(mol)xx6.022xx10^23*cancel(mol^-1)#, approx. #1.0xx10^22# #"carbon dioxide molecules"#. We get the answer as a number as required.

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