How do you expand and simplify $2 (3 x + 4) - 3 (4 x - 5)$ $2(3x+4)-3(4x-5)$ ?

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Answer 1 · 2016-12-13T04:27:36

$- 6 x + 23$ $-6x + 23$

Step 1) Distribute the constant outside each parenthesis across each term within their respective parenthesis:

$((2 \cdot 3 x) + (2 \cdot 4)) - ((3 \cdot 4 x) - (3 \cdot 5))$ $((2*3x) + (2*4)) - ((3*4x) - (3*5))$

$(6 x + 8) - (12 x - 15)$ $(6x + 8) - (12x - 15)$

Step 2) Remove the parenthesis, be careful to manage the signs correctly and then group like terms:

$6 x + 8 - 12 x + 15$ $6x + 8 - 12x color(red)(+) 15$

$6 x - 12 x + 8 + 15$ $6x - 12x + 8 + 15$

Step 3) Combine like terms:

$(6 - 12) x + 23$ $(6 - 12)x + 23$

$- 6 x + 23$ $-6x + 23$

How do you expand and simplify 2(3x+4)-3(4x-5)2(3x+4)−3(4x−5)2(3x+4)-3(4x-5)?