Question

A 5.00 liter balloon of gas at 25 C is cooled to 0 C. What is the new volume (liters) of the balloon?

Answer 1

We use `"Charles' Law"`, `V_1/T_1=V_2/T_2`

Explanation:

`T` is specified to be `"Absolute Temperature"`:

`V_2=V_1/T_1xxT_2`

`= (5.00*L)/(298*K)xx273*K~=4.5*L`