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Answer 1 · 2016-12-15T08:09:29

Simply multiply the #"molar volume"# by the amount in #"moles"#.

#"Molar volume "xx" molar quantity"#

#=82.4*mL*cancel(mol^-1)xx250xx10^-3*cancel(mol)~=20*mL#

And when we do the problem dimensionally in this manner we automatically get an answer in #mL# as required.

Answer 2 · 2016-12-15T08:11:18

Amount of liquid octane #=250mmol=250xx10^-3mol#

Volume this octane

#="no of mole"xx"molar volume"#

#=250xx10^-3molxx82.4"ml"/"mol"#

#=20.6ml#