Question

How do you evaluate the definite integral `int(2x+2)dx` from `[-3,1]`?

Answer 1

`0`

Explanation:

Integrate each term using the `color(blue)"power rule for integration"`

`color(orange)"Reminder " color(red)(bar(ul(|color(white)(2/2)color(black)(intax^ndx=a/(n+1)x^(n+1))color(white)(2/2)|)))`

`rArrint_-3^1(2x+2)dx=[x^2+2x]_-3^1`

Now, subtract the evaluation of the lower limit from the evaluation of the upper limit.

`rArr(1+2)-(9-6)=3-3=0`