Question #75d2f

1 Answer
Dwight
Dec 16, 2016

the yield is 80%, as you say.

Explanation:

You start by showing that 0.100 mol #C_8H_18# should yield 0.80 mol of #CO_2#, becaus the equation shows the ratio between these to is 2 to 16 or 1 to 8.

0.80 mol of #CO_2# would have a mass of 0.8 x 44 = 35.2 g

Because the yield was only 28.16 g, rather than 352.g, the percentage yield is

#28.16/35.2# x #100# = 80% (to two digits)

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