A charge of #16 C# passes through a circuit every #12 s#. If the circuit can generate #1 W# of power, what is the circuit's resistance?

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Answer 1 · 2016-12-17T16:31:29

#= 1.78Ω (3s.f.)#

#I = C / t#

#I = (16C) / (12s) = 4/3 A#

#R = P / I^2#

#= (1W) / ((4/3)^2A)#

#= (1W) / ((9/16)A)#

#1/(9/16)Ω = 16/9Ω#

#= 1.78Ω (3s.f.)#