A charge of 16 C16C passes through a circuit every 12 s12s. If the circuit can generate 1 W1W of power, what is the circuit's resistance?

1 Answer
Dec 17, 2016

= 1.78Ω (3s.f.)

Explanation:

I = C / t

I = (16C) / (12s) = 4/3 A

R = P / I^2

= (1W) / ((4/3)^2A)

= (1W) / ((9/16)A)

1/(9/16)Ω = 16/9Ω

= 1.78Ω (3s.f.)