Question

How do you solve `\sqrt { 3y } = 2\sqrt { y + 5}`?

Answer 1

I didn't get any real solution.

Explanation:

We can try by squaring both sides to get:
`(sqrt(3y))^2=(2sqrt(y+5))^2`
`3y=4(y+5)`
`3y-4y=20`
`y=-20`
unfortunately this solution cannot be accepted because it would get you a negative argument in the original square roots...it would work if you consider imaginary numbers though, where you can consider a negative argument for a square root!