How do you solve #81m^2=64#?

2 Answers
Dec 18, 2016

#m=-8/9 or m=+8/9#

Explanation:

Since #81m^2=(9m)^2#
#81m^2=64#
#rarrcolor(white)("XXX")(9m)^2=64#
then taking the square root of both sides
#rarrcolor(white)("XXX")9m=+-8#
or
#color(white)("XXXXX")m=+-8/9#

Dec 18, 2016

#m=+-8/9#

Explanation:

Given:#" "81m^2=64#

Divide both sides by 81

#81/81xxm^2=64/81#

But #81/81=1#

#m^2=64/81#

Square root both sides

#m=+-sqrt(64/81)#

#m=+-sqrt(64)/sqrt(81)#

#m=+-8/9#
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Why is this #+-#?

Consider the example: #(+2)xx(+2)=(-2)xx(-2)= +4#

If the signs are the same in multiply or divide then the answer is positive.

So #m^2=(-8/9)^2=(+8/9)^2#

So #m=+-8/9#