Question

How do you find g(1/3) given `g(x)=x^2-x`?

Answer 1

`-2/9`

Explanation:

`g(x)=x^2-x`

`g(1/3)" "`means we replace all the `""xs" "`in the equation with`" "1/3""`

`g(1/3)=(1/3)^2-(1/3)`

`g(x)=1/9-1/3=1/9-3/9=-2/9`