Question #81787

Question

2077 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-12-19T17:11:39

Range =#sf(1019color(white)(x)m)#

#sf(T=14.4color(white)(x)s)#

MFDocs

To get the time of flight T use:

#sf(v=u+at)#

To get the time t to reach the maximum height, take vertical components of motion:

#sf(0=vsintheta-"gt")#

#:.##sf(t=(vsintheta)/g=(100sin45)/9.81=7.208color(white)(x)s)#

Since the motion is symmetrical we can say that the total time of flight T will be given by:

#sf(T=2t=2xx7.208=14.41color(white)(x)s)#

To get the range use the horizontal component of velocity which is constant.

#sf(s=vcosthetaxxt)#

#:.##sf(s=100cos45xx14.41=1019color(white)(x)m)#