What is the speed of a satellite moving in a stable circular orbit about the Earth at a height of 4000 km?

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Answer 1 · 2016-12-20T02:42:17

#v_0= 6.197 xx 10^3m/s#

The reference for Orbital Speed gives us the following equation:

#v_0= sqrt((GM)/r)#

Where,

#M# is the mass of the Earth #(5.972 xx 10^24" kg")#,

#G# is the gravitational constant #(6.674 xx 10^-11" m"^3/(kgcolor(white)•s^2))#

and #r# is the radius of the Earth plus the height of the orbit #(1.0378xx10^7" m")#

#v_0= sqrt(((6.674 xx 10^-11" m"^3/(kgcolor(white)•s^2))(5.972 xx 10^24" kg"))/(1.0378xx10^7" m"))#

#v_0= 6.197 xx 10^3m/s#